
Paolo S. answered 12/14/20
PhD student with 5+ years of Tutoring and Teaching Chemistry Labs
2S10Br3(g) + 10Se(s) ----> 3Br2(g) + 10SeS2(s)
Once we write the equation we see right away that we would need 2 equivalents of S10Br3 to form 3 of Br2 by simply balancing it. Also, this would require 10 eq. of Se(s). Finally, we have a 10/3 molar ratio between SeS2 and Br2 which would give us 16.53 moles of SeS2. We multiply by the molar mass (143.09 g/mol) and we get 2365.8 g of SeS2.