Absolutely not! F_{g} = Gm_{1}m_{2 / R}^{2} ; where R represents the distance between the center of mass of two objects, in this case the center of the earth & tree, so if the height of the tree doubled that added distance would statistically be INSIGNIFICANT, so wouldn’t measurably alter the gravitational force.

Jenson J.

asked • 12/14/20# physics, rotational motion, gravitation, question is in description

Consider an apple at the top of a tree that is pulled by Earth’s gravity with a force of 1 N. If the tree were twice as tall, would the force of gravity be only ¼ as strong? Defend your answer.

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