Raymond B. answered 01/04/21
Math, microeconomics or criminal justice
add x^2 to both sides, also add 5 to both sides to get
5>5x^2, now divide by 5
1> x^2
x^2<1
two ways x^2 < 1
take the square root of both sides to get x<1 and x>-1 simultaneously
-1<x < 1
that's the same as the answer you have, with an intersection of x<1 and x>-1
to see that maybe try a few simple integers in that interval and outside
x=0. x^2 = 0^2 = 0 <1
x=2 x^2 =2^2 = 4 which is not < 1
x=-2 x^2 = (-2)^2 = 4 which is also not <1
the absolute value of x has to be less than 1, which means x<1 and -x<1. -x<1 is equivalent to x>-1. Multiply by -1 reverses the inequality from < to >