Sanika P. answered 12/14/20
Experienced STEM Tutor for students of all ages
The C double bonded to O, followed by a OCH3 group is an acetate group. Using this knowledge we can solve the two problems.
Problem 1:
We that we have an acute group bonded to a CH3, or in other words a methyl group. By putting the two parts of the compound together we can determine that the compound is methyl acetate.
Problem 2:
Start off by counting the number of carbons right in the acetate group. There are four carbons (C=O, CH2, CH2, CH3). We know we have a butanoate; butan- is the suffix for a four carbon chain and -oate is the suffix for an acetate group. Now let's count the number of carbons left of the carbonyl (C=O). There are 3 carbons; we know that that is a propyl group then. By putting the two parts together we know the name of the compound is propyl butanoate.

