Getting frustrated for the programming question below. Please give me a hand for some help.

Question

Utilizing the same windows32 framework below, implement a program that will use a dialog box to prompt for an integer n, compute the sum 1² + 2² + . . . + n² , and use a message box to display the sum. Use a loop in the implementation.

.586

.MODEL FLAT

INCLUDE io.h           ; header file for input/output

.STACK 4096

.DATA

number1 DWORD  ?

number2 DWORD  ?

prompt1 BYTE   "Enter first number", 0

prompt2 BYTE   "Enter second number", 0

string BYTE   40 DUP (?)

resultLbl BYTE "The sum is", 0

sum    BYTE   11 DUP (?), 0

.CODE

_MainProc PROC

       input  prompt1, string, 40     ; read ASCII characters

       atod   string         ; convert to integer

       mov    number1, eax   ; store in memory

       input  prompt2, string, 40     ; repeat for second number

       atod   string

       mov    number2, eax

       

       mov    eax, number1   ; first number to EAX

       add    eax, number2   ; add second number

       dtoa   sum, eax       ; convert to ASCII characters

       output resultLbl, sum         ; output label and sum

       mov    eax, 0 ; exit with return code 0

       ret

_MainProc ENDP

END                            ; end of source code

Answer 1

Hi Tri,

What is the logic that you are trying to follow? If you have to find the sum of 1² + 2² + . . . + n^2.. . You need to get the number 'n' from the end-user and run a for loop to get the sum. Here is the algorithm that you can follow:

int sum = 0; // Define a variable 'sum' to get the cumulative sum

//Following loop is to check if value of n greater than zero.

while loop( condition(n>0){

sum = sum + n².

n-- //Decrement value of n

}

Hope this helps!!