Hi Kyle,
The molar mass of aluminum is 26.982 g/mol. The molar mass of oxygen is 15.999 g/mol. Therefore, the molar mass of Al2O3 is 2(26.982 g/mol) + 3(15.999 g/mol) = 101.961 g/mol.
The percent aluminum in Al2O3 is 100% * 2(26.982 g/mol) / 101.961 g/mol = 52.926%.
The largest mass of aluminum that can be obtained from a 2,000 g sample of Al2O3 is 52.926% * 2,000 g = 1059 g.
Hope this helps!