Stoichiometric Calculations

Question

C2H4 + 3O2 2CO2 + 2H2O

Given 15.0 g of ethene (C2H4) ( and excess oxygen):

How many moles of water will be produced?

How many grams of carbon dioxide will be produced?

with work out please

Answer 1

Basically a simple stoichiometry problem:

15.0g ethane/1 X 1 mol ethane/28.0g ethane X 2 mol H₂O/1 mol ethane = 1.07 mol H₂O

15.0g ethane/1 X 1 mol ethane/ 28.0g X 2mol CO₂/ 1 mol ethane X 44g CO₂/ 1 mol CO₂ = 47.1 g CO₂

Answer 2

C2H4+3O2=2CO2+2H2O

molar mass of ethene is 28,

In the reaction, 1 mole of C2H4 generates 2 moles H2O, namely 28g C2H4 generates 2 moles H2O.

So 15g C2H4 generates H2O 15/28*2=1.07 mol