Vinidu G.
asked • 12/09/20A girl reaches out of a window and tosses a ball straight up with a speed of 10 m/s. The ball is 20 meters above the ground as she releases it.
A girl reaches out of a window and tosses a ball straight up with a speed of 10 m/s. The ball is 20 meters above the ground as she releases it.
a. How high does the ball rise above the ground?
b. What is the speed of the ball just before hitting the ground?
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1 Expert Answer
Sunil K. answered • 12/09/20
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a. v^2=u^2-2gh, h=5.1m, Hence the total height from the ground, H=20+5.1m = 25.1m.
b. v^2=u^2+2gH, H=25.1m, u=0 (velocity at the top of trajectory), Therefore, v= 22.18m/s
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Sunil K.
a. use the equation of motion , v^2=u^2-2gh, which gives you h=5.1m, hence the total height from the ground is 20+5.1=25.1 m. b. use v^2=u^2+2gH, H=25.1m, u=0m/s (at the top of trajectory), this gives you, v = 22.18 m/s.12/09/20