chemistry question

Question

What is the mass of 0.233 mol nickel(ii) chloride?

Answer 1

First, you need to find out the molar formula of nickel(II) chloride. The (II) in the middle means that the nickel ion(s) each have a charge of +2. We also know that chloride ions always have a charge of -1. What is the least number of nickel and chloride ions we can put together so that their total charge equals zero?

Tha answer is 1 nickel and two chlorides, so the molar formula is NiCl2. So, for every mole of nickel(II) chloride, there is one mole of nickel (Ni2+) and two moles of chloride (Cl-).

We know that we have 0.233 moles of nickel(II) chloride, which breaks down to 0.233 moles of Ni2+ and 0.466 moles of Cl-. Simply multiply the number of moles by the atomic mass to get the mass of each element.

0.233 moles Ni2+ × 58.6934 g/mole = 13. 676 g

0.466 moles Cl- × 35.453 g/mole = 16.521 g

Ado the mass of the Ni2+ and the Cl- to get the total mass of the nickel(II) chloride.

13.676 g + 16.521 g = 30.197 g