whats the answer

Question

Which equation describes a line that passes through (-6, 8) and is perpendicular to the line described by ?

y=−2x−4

y=−1/2x+5

y=1/2x+11

y=2x+20

Answer 1

y=(1/2)x + b

8=(1/2)(-6) + b

8=-3 + b

b = 11

y=(1/2)x + 11

y=2x + b

8=2(-6) + b

8=-12 +b

b =20

y=2x +20

y=-2x + b

8=-2(-6) + b

b =-4

y=-2x-4

y=-(1/2)x + b

8=-(1/2)(-6) + b

b = 2

y=-x/2 +2