Daniel M.

asked • 12/04/20

How can I solve this physics question? Please and thank you

A hanging weight with a mass of m1 = 0.375 kg, is attached by a string to a block with mass m2 = 0.865 kg. The string goes over a pulley with a mass of M = 0.350 kg, and the pulley is a hollow cylinder with an inner radius of R1 = 0.0200 m and an outer radius of R2 = 0.0300 m. The coefficient of kinetic friction between the block and the table is μk = 0.250. The block is moving with a velocity of vi = 0.820 m/s toward the pulley.



A. Using energy methods, find the speed of the block (in m/s) after it has moved a distance of 0.700 m away from the initial position shown.


 _____m/s


B. What is the angular speed of the pulley (in rad/s) after the block has moved this distance?


 _____ rad/s


1 Expert Answer

By:

Greg S. answered • 12/04/20

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Daniel M.

We just started this topic so I have literally no idea what you just said. I have a tutor and I'm working on concepts but right now I just need to see what I have to do so I can figure it out with more practice. Thank you though.
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12/05/20

Greg S.

If you're just starting, this is a pretty complex problem to give you. Before tackling a problem that includes angular momentum and rotational energy--or a problem where you have to add up work done in various systems, you usually have been through kinematics, forces, work, momentum, and conservation of energy in simpler systems. With all that in place, my explanation should have made sense. That said, let me illustrate the principles with a simpler system: for instance, with a massless pully and string where a mass m1 falls through distance h while also pulling on a mass of m2 on frictionless horizontal surface. As m1 falls, it does work = to it's change in potential energy, mgh on the entire system. Since the moving system has kinetic energy of (1/2)(m1+m2)v^2, you can set that = to mgh to find the final speed of the system after it falls some distance h. This problem is similar, except you have to account for all the places that energy goes. To both moving blocks, the work done against friction, and the energy imparted to the pully. I have to tutor in 30 minutes for 2 hours; after that I'll take a crack at showing you how this whole thing works out. I just don't want to do all the work and simply give you the answer without a full explanation. Your goal will be to fully understand all the parts of this. Given the complexity of this problem, you can expect more like it from your instructor.
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12/05/20

Greg S.

Perhaps it is too late now, but I have worked this out completely for you now. However, it needs a video answer which I cannot do here. Contact me if still need the answer.
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12/05/20

Greg S.

Perhaps it is too late now, but I have worked this out completely for you now. However, it needs a video answer which I cannot do here. Contact me if still need the answer.
Report

12/05/20

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