The parabola that passes through the point (8, −2), with vertex V(2, −1) and vertical axis of symmetry

Answer 1

y+1 = a(x-2)^2

-2 + 1 = a(8-2)^2

-1 =36a

a = -1/36

y+1 =(-1/36)(x-2)^2

36y+36 =-x^2 +4x -4

36y = -x^2 +4x -40