How many moles of MgCO3 are in 2.57g of MgCO3?

Answer 1

First determine the molar mass of MgCO₃ by adding up the atomic weight of each individual component. The atomic weights of Mg, C, and O are 24.305 g/mol, 12.011 g/mol, and 15.9994 g/mol, respectively.

24.305 + 12.011 + 3*15.9994 = 84.31 g/mol

Now the molar mass of the molecule can be used as a conversion factor

2.57 g * (1 mol / 84.31 g) = 0.0305 mol MgCO₃