If an ideal gas occupies 3.00 L at 2.00 atm of pressure, how many liters does it occupy when the pressure is increased to 10.15 atm? Assume the temperature remains constant.

Answer 1

P1 V1=P2 V2

P1= 2.0 atm

P2= 10.15 atm

V1= 3.00 L

V2= ?

2.00atm X 3.00L = 10.15atm x V2

2.00atm X 3.00L / 10.15atm = V2

Answer: 0.5911 L = 0.6 L