Brianna M.

asked • 11/26/20

chemistry question

Hydrazine, N2H4 , reacts with oxygen to form nitrogen gas and water.


N2H4(aq)+O2(g)⟶N2(g)+2H2O(l)


If 3.05 g of N2H4 reacts with excess oxygen and produces 0.450 L of N2 , at 295 K and 1.00 atm, what is the percent yield of the reaction?


1 Expert Answer

By:

J.R. S.

tutor
(3.05 g N2H4)(1 mol N2H4/32.045 g N2H4)(1 mol N2H4/ 1 mol N2) ( 28.01 g N2/ 1 mol N2) = 2.67 grams N2 should be (3.05 g N2H4)(1 mol N2H4/32.045 g N2H4)(1 N2/ 1 mol N2H4) ( 28.01 g N2/ 1 mol N2) = 2.67 grams N2
Report

11/27/20

Joyce T.

tutor
thank you for catching that error!
Report

11/27/20

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