C(20, 8) = 20! ÷ [(8)!*(12)!] =

Question

A caterer offers 20 different types of dessert. In how many ways can 8 of them be chosen for a banquet if the order doesn’t matter?

Answer 1

C(20, 8) = [(20!)/(8!*12!)] = 125,970

The caterer has 125,970 ways to choose 8 desserts out of the 20 for a banquet if order doesn't matter.

20! ÷ 8! ÷ 12! = 2,432,902,008,176,640,000 ÷ 40,320 ÷ 479,001,600 = 125,970