Determine the mass of 1.57 kmol sulfur trioxide. Answer has to be in grams.

Answer 1

First, we need to determine the molecular structure of sulfur trioxide. Sulfur trioxide is composed of one sulfur atom and three oxygen atoms, giving it a molecular formula of SO₃.

Let's now determine the molar mass of sulfur trioxide, which we can use to convert from mol to grams. Sulfur has a molar mass of 32.06 g/mol and oxygen has a molar mass of 15.999 g/mol. To find the molar mass of this molecule we need to add up these weights. We have three oxygen molecules so we multiply the molar mass of oxygen by three and add it to the molar mass of sulfur to get a total molar mass of 80.057 g/mol [ 3(15.999) + 1(32.06) = 80.057 ].

Now that we have the molar mass of the molecule we can convert kmol to mol and then use the molar mass we calculated to convert mol to grams.

1 kmol = 1000 mol

1.57 kmol = 1570 mol

1570 mol x 80.057 g / 1 mol = 125,689 grams sulfur trioxide