Graph of the parabola #4

Question

Find the equation of the parabola with vertex at (-3, 1) and the focus at (1, 1). Sketch the graph.

Answer 1

x=a(y-1)^2 -3

1=64a -3

a =1/16

x= (1/16)(y-1)^2 -3

it's a rightward opening parabola