x = ay^2 vertex (0,0), focus (-2,0) directrix x= 2
to find "a" the leading coefficient, plug in any other point, such as (-2,4)
-2 = 16a
a =-1/8
x=(-1/8)y^2
Laci M.
asked 11/22/20find the standard form of the equation of the parabola with the given characteristics and vertex at the origin.
Focus (-2,0)
x = ay^2 vertex (0,0), focus (-2,0) directrix x= 2
to find "a" the leading coefficient, plug in any other point, such as (-2,4)
-2 = 16a
a =-1/8
x=(-1/8)y^2
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.