How do I do this? Let f and g be differentiable functions such that f′(0)=3 and g′(0)=7. If h(x)=3f(x)−2g(x)−5cosx−3, what is the value of h′(0) ?

Answer 1

-5

H' = 3 f' -2 g' +5 sin x

3*3-2*7