
Mike D. answered 11/18/20
Experienced high school discrete math teacher
x mod 2 = k then x = 2m + k where m is an integer
y mod 2 = l then y = 2n + l where l is an integer
xy = (2m + k) (2n + l) = 4mn + 2ml + 2kn + kl = 2 (2mn + ml + kn) + kl
xy mod 2 = kl
(x mod 2) (y mod 2) = kl
Proved