If a reaction causes 20.0 mL of water to increase temperature by 10.0 oC at constant pressure, what would be the change in temperature if 60.0 mL of water were used instead?

Question

If a reaction causes 20.0 mL of water to increase temperature by 10.0 ^oC at constant pressure, what would be the change in temperature if 60.0 mL of water were used instead? Assume change in enthalpy of the reaction remains the same

Answer 1

60mL of water is 3 times the mass of 20mL of water

q=mcΔt

q=20(c)(10)

q=(20*3)(c)(30)

It'll cause the temperature to change 3 times as much.