Let x = number of gallons of 30% type and y = number of gallons of 80% type
Then, x + y = 90 and 0.30x + 0.80y = 0.70(90)
x + y = 90
30x + 80y = 6300
-30x - 30y = -2700
30x + 80y = 6300
50y = 3600
y = 72 gal and x = 18 gal
Kristen N.
asked 11/15/20A chemical company makes two brands of antifreeze. The first brand is 30% pure antifreeze, and the second brand is 80% pure antifreeze. In order to obtain 90 gallons of a mixture that contains 70% pure antifreeze, how many gallons of each brand of antifreeze must be used?
First brand:
Second brand:
Let x = number of gallons of 30% type and y = number of gallons of 80% type
Then, x + y = 90 and 0.30x + 0.80y = 0.70(90)
x + y = 90
30x + 80y = 6300
-30x - 30y = -2700
30x + 80y = 6300
50y = 3600
y = 72 gal and x = 18 gal
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