A 115.8 mL sample of carbon dioxide was heated to 339 K. If the volume of the carbon dioxide sample at 339 K is 365.1 mL, what was its temperature at 115.8 mL?

Answer 1

Assuming Ideal Gas Law:

Volume is directly proportional to temperature.

Therefore, V1/T1=V2/T2

Lets see what we have from the given problem:

V1=115.8 ml

T1= unknown

V2= 365.1 ml

T2= 339K

Plug in to solve for T1:

T1= 115.8*(339/365.1)

T1=107.52K