A sealed container holding 0.0255 L of an ideal gas at 0.983 atm and 71 ∘C is placed into a refrigerator and cooled to 41 ∘C with no change in volume. Calculate the final pressure of the gas.

Answer 1

With an Ideal Gas and constant volume, pressure and temperature are related by the following equation:

P1/T1=P2/T2

Lets see the variables given to us from the question:

P1 = 0.983 atm

T1 = 71C = 344.15K

P2= unknown

T2 = 41C = 314.15K

Plug into equation:

P2= 0.983*314.15/344.15

P2 = 0.8973 atm