Solving a decimal word problem using a two-step linear inequality

Question

To rent a certain meeting room, a college charges a reservation fee of $39 and an additional fee of $8.70 per hour. The chemistry club wants to spend at most $108.60 on renting the meeting room. What are the possible amounts of time for which they could rent the meeting room?

Use t for the number of hours the meeting room is rented, and solve your inequality for T.

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Answer 1

Let t = the # of hours the meeting room is rented There is a one time fee of $39 so we'll add that to the cost. Then it's $8.70 PER hour, or PER t.

So we have 39 + 8.70t We want this amount to be LESS than (or equal to) the amount of money we have to spend, which is $108.60.

So, 39 + 8.70t < (or equal to) 108.70. (I'm not sure how to get the "less than or equal to" symbol)

39 + 8.70t < (or equal to) 108.70 Solve this for t. Get t by itself.

The answer will be how many hours you can rent the room for.

Any questions? I hope his helps!

-Margaret

Answer 2

T<8

8 hours is the maximum to stay = or under the $108.60 budget

108.6 > 39 + 8.7T

8.7T < 108.6-39

T < 69.6/8.7

T < 8 hours

8 x 8.7 + 39 = 108.6