Can't see the diagram of course but the relationship is Heat Flow (Qdot)= Conductivity*Area*delta T. Conductivity = 200 J/sec-m^2-degrees ... calculate the area for each of the indicated faces in the diagram and apply the formula to each.
Garrett J.
asked 11/11/20The block in the drawing has Dimension L0x2L0x3L0
The block in the drawing has dimensions L0x2L0x3L0, where L0=.5m The block has a thermal conductivity of 200 J/(s·m·C˚). In drawings A, B, and C, heat is conducted through the block in three different directions; in each case the temperature of the warmer surface is 29 ˚C and that of the cooler surface is 16 ˚C Determine the heat that flows in 5 s for each case.
Picture A is of the block with an arrow going through it from left to right
Picture B has the arrow going front to back
Picture C has the arrow going Bottom to top.
a. Q=
b. Q=
c. Q=
I don't understand this question, If you can help, I would appreciate it!
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