4.48 g of sodium carbonate is recovered from the decomposition of 2.64 g of sodium bicarbonate, what the percent yield of the reaction? 2 NaHCO 3 (s) Na 2 CO 3 (s)+CO 2 (g)+H 2 O(l)

Answer 1

1. Find the theoretical yield (amount of Na2CO3 that you expected to form) using stoichiometry:

2.64 g NaHCO3 -> mol NaHCO3 -> mol Na2CO3 -> g Na2CO3

1. Find the percent yield using the formula:

% yield = [(actual yield) / (theoretical yield)] x 100

1. the actual yield was given: 4.48 g Na2CO3
2. the theoretical yield is what you just calculated using stoichiometry

Let me know if that helps/if you need further clarification!