A sample of an ideal gas has a volume of 3.55 L at 14.60 ∘C and 1.90 atm. What is the volume of the gas at 19.80 ∘C and 0.990 atm?

Question

A sample of an ideal gas has a volume of 3.55 L at 14.60 ∘C and 1.90 atm. What is the volume of the gas at 19.80 ∘C and 0.990 atm?

Answer 1

For this question, the Combined Gas Law is used: (P₁V₁/T₁) = (P₂V₂/T₂) and isolate the solve for V₂:

V₂ = (P₁V₁T₂/P₂T₁) Convert the temps from Celsius to Kelvins by adding 273.15; put in the terms, and solve.

V₂ = [(1.90 atm) (3.55 L) (287.75 K)] / [(0.990 atm) (292.95 K)] = 6.692 = 6.69 L