A race car has to cover 50 k. fuel for max dist of 53k Dist given by S(t)=3t+47, t is time in hrs. Whats min&max hrs?

Question

Alan participated in a car race in which he had to cover at least 50 k. He had fuel in his car for a maximum distance of 53 k. If the distance is given by S(t)=3t+47, where t is the time in hours, find the minimum and maximum number of hours for which Alan can drive his car.

Answer 1

It sounds like you want the distance to be at least 50 and at most 53.  So set up the compound inequality 

 

50 <= 3t + 47 <= 53  

 

and solve to get

 

3 <= 3t <= 6

1 <= t <= 2

 

So the minimum time is 1 hour and the maximum time is 2 hours.