power produced by gas

Question

equation given is 2SO2(g)+O2(g)->2SO3(g),

and if 224L/h of O2 (at standard temp and pressure) is consumed by the reaction,

 

how much power is produced?

I can't go further than P=Work/Time and Work=P times change in V

I've tried 224x2/60^2 but that's not the answer :(
Some help would be much appreciated!

Answer 1

1. We know 224 L/h of O2 is consumed at standard temperature and pressure (STP)
2. To calculate power, we'll need to:
3. Calculate the moles of O2
4. Determine the heat of reaction
5. Convert heat to power
6. At STP, 1 mole of gas occupies 22.4 L
7. Moles of O2 = 224 L ÷ 22.4 L/mol = 10 moles/h
8. From the balanced equation, 1 mole O2 produces 2 moles SO3
9. The heat of reaction for SO3 formation is approximately -99 kJ/mol
10. this is the standard enthalpy for this reaction that can be found in the back of any chemistry text book
11. Total heat = 10 moles/h × 2 mol SO3/mol O2 × (-99 kJ/mol)
12. = -1,980 kJ/h
13. Power = 1,980 W (1 kJ/s = 1 kW)

The reaction produces approximately 1,980 watts of power.