Kathy P. answered 10/28/20
Mechanical Engineer with 10+ years of teaching and tutoring experience
Let's call the angle x instead of theta!
secant(x) > 0
secant(x) = 1/cos(x) > 0
If secant(x) is positive, cos(x) is also positive.
Positive cos(x). ==> Q1 or Q4
cos(x) * tan(x) < 0
cos(x) * sin(x)/cos(x) < 0
sin(x) < 0
Negative sin(x) ==> Q3 or Q4
ANSWER: The angle is in Q4