An ideal gas in a sealed container has an initial volume of 2.70 L. At constant pressure, it is cooled to 24.00 ∘C, where its final volume is 1.75 L. What was the initial temperature?

Answer 1

For the ideal gas, pressure (P) is kept constant here

Initial volume, V1 = 2.70L

Temperature, T1 = ?

final volume, V2 = 1.75L

final temperature, T2 = 24.00 degree C

As its clear from the given values Charles Law applies here,

volume of a given gas is directly proportional to its absolute temperature at constant pressure.

V/T= Constant, V1/T1= V2/T2 ---------------------------------------1

Absolute temperature = (temp in degree C + 273) K ---------------------2

T2 = 24.00+ 273

T2 = 297K

apply V1, V2 and T1 for equation 1 to find T2

2.70/T1=1.75/297

T1 = (297*2.70)/1.75

T1 = 458.23K

again convert temperature to degree C by applying in equation 2

458.23 = temp in degree C + 273K

Temp in degree C = 185.23 degree C.