Pasquale D. answered 10/30/20
High School/College Math Tutor
B. Since , either
,
, or
and
. Suppose
. Then
. Either
or
. Suppose
. Thus,
. That is, it's possible that
to be false.
Going one step further, we just showed that there exists an element such that
, but
; that is, we showed that
is not a subset of
. So, the original statement is false and can't actually be proved, if that makes any sense.
You can prove, however, that ; in fact, you can prove the reverse containment as well:
, which means that
.