the number of grams of hydrogen in the mixture is g.

Question

A mixture of xenon and hydrogen gases is maintained in a 6.64 L flask at a pressure of 3.75 atm and a temperature of 45 °C. If the gas mixture contains 88.0 grams of xenon, the number of grams of hydrogen in the mixture is   g?

Answer 1

Hello, HS,

I'm concerned about the number of conversions I needed, but here's what I did:

Use the gas law PV = nRT

n is the total number of moles of both H2 and Ar. Calculate the number of moles of Ar (0.672) and then PV. The value of PV is 24.9 L*atm. This needs to be converted to Joules, since the R value I used is expressed in J⋅K⁻¹⋅mol⁻¹. I used . R is .

Calculate RT, but convert C into K, first (again, due to the R unit). Solve for n = PV/RT. I get 0.954 moles total gas. Subtract the Ar moles to arrive at 0.2828 moles H2. I see 2 sig figs in the temperature, but I'll let you decide what should be reported.

Bob