Inactive Tutor answered 10/22/20
Here we have to solve for the minimum speed to ensure the rider won't slide down the wall. In other words, when does the centripetal force equal the frictional force, so:
Fc = Fg where
Fc = mv2/r
Fg = μN = μmg
mv2/r = μmg
v2/r = μg
v2 = μgr
v = √μgr
v = √(0.175)(9.81)(6) = 3.2 m/s