Word problem finding the three numbers !

Question

the sum of three numbers is 136. the third number is 8 more than the first. the second number is 4 times the third.what are the numbers?

Answer 1

The numbers we want can be written like: x + y + z = 136

The third number is 8 more than the first: (8 + x)

The second number is 4 times the third: 4(8 + x) or 32 + 4x

So you can rewrite the first equation x + y + z = 136 as x + 4(8 + x) + (8 + x) = 136

Now multiply 4 time (8 + x) to get x + 32 + 4x + 8 + x = 136

Now combine all x's and all numbers to get: 6x + 40 = 136

Subtract the 40: 6x = 96

Divide by 6: x = 16

Now that you know what x is you can plug it in to the initial formulas we made:

The first number is x: 16

The third number: (8 + x) -> (8 + 16) = 24

The second number: 4(8 + x) or 32 + 4x = 32 + 4*16 = 96

Answer: 16, 24, 96