The HCl has nothing to do with the question (& it doesn't make sense to mention it because it will react with the Zn!)
Zn(s) + CuSO4(aq) → Cu(s) + ZnSO4(aq)
(63.55 g Cu/1 mol Cu) (1 mol Cu/1 mol Zn) (1 mol Zn/65.38 g Zn) 2.0 g Zn = 1.9 g Cu (2 sig figs)