
Anthony T. answered 10/21/20
Patient Science Tutor
As the amount of CuO is not specified, we will assume it is there in excess. The balanced equation is CuO + H2SO4 → CuSO4 + H2O. The concentration and volume of sulfuric acid is given; therefore, we can calculate the number of moles and grams of sulfuric acid involved in the reaction. The number of moles of H2SO4 is 6M/L/1000 mL x 15 mL = 0.090 moles. The mass of this is obtained by 0.09 x molecular weight of H2SO4 or 0.090 x 98.1 = 8.83g. The number of grams of CuSO4 produced is given by the proportion 8.83g/98.1g = x/159.6g. Solve for x to get the mass of CuSO4 produced.
Answer: 14 g of CuSO4 to two significant figures.