Alex B.

asked • 10/20/20

Honors chemistry

How many miles of potassium nitrate would be necessary to prepare 116.4 g of lead(II) nitrate?

Pb(NO3)2(aq) + 2 KI(aq) + 2 KNO3(aq)

J.R. S.

tutor
You might want to review this equation because lead(II) nitrate isn't a product as written. What is the actual reaction you want to investigate?
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10/21/20

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