
Artem Z. answered 02/17/15
Tutor
4.3
(11)
SJSU EE: Math, Physics, Circuits, Writing, Music
This is a 2-part algebraic problem relating to mass/density/volume and the volume of a sphere.
Proton's radius (Rp) = 1.0 x (10^-13) cm = (1/100) x (10^-13) m = 1.0 x (10^-15) m
Proton's mass (Mp) = 1.7 x (10^-24) g = (1.7/1000) x (10^-24) kg = 1.7 x (10^-27) kg
Proton's volume (Vp) = (4/3)pi(r^3)
Density (Dp) = mass (Mp) / volume (Vp)
Dp = Mp/Vp = Mp / (4/3)pi(Rp^3) = (3*Mp) / (4pi(Rp^3))
Dp = 3(1.7 x (10^-24) g) / [4pi(1.0 x (10^-13)) cm^3]
Dp = 4.05845105 x (10^-12) g/(cm^3)
If you needed to give your answer in units of meters/kilograms cubed (m/kg^3), then
Dp = 4.05845105 x (10^-13) kg/(m^3)