
Patrick B. answered 10/19/20
Math and computer tutor/teacher
Suppose not...
Suppose the product of an irrational and rational is RATIONAL...
Then by contradiction x * y = z for irrational x and rationals y and z
Since y and z are rational , y = a/b and z = m/n for integers a,b,m,n with a,b and m all not zero
Substitution:
x ( a/b) = m/n
Multiplying by b/a:
x = (m/n)(b/a) = (mb)/(an)
By closure property of integer multiplication , mb and an are integers
so then x is the quotient of two integers, which makes it rational, a contradiction