sqrt(108)/12 = sqrt(36)sqrt(3)/12 = 6* sqrt(3)/12 = sqrt(3)/2
cos(theta) = sqrt(3)/2 ---> theta = 30 degrees or PI/6 radians
Caroline S.
asked 10/17/20Suppose that cosθ=√108/12
What is the value of θ? Give your answer in radians and degrees.
Assume that θ is an acute angle.
sqrt(108)/12 = sqrt(36)sqrt(3)/12 = 6* sqrt(3)/12 = sqrt(3)/2
cos(theta) = sqrt(3)/2 ---> theta = 30 degrees or PI/6 radians
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