Brian F. answered 10/17/20
Patient & Energetic Math Tutor
Hey Mikayla,
For some random variable X with possible values x1, x2, ... , xn, the expected value, E[X], is the probability-weighted sum of possible values. In other words, the expected value is the result of adding up each possible outcome multiplied by the probability that particular outcome occurs.
In your problem, there are three random variables: the card drawn from the 52-card deck, the result of the coin flip, and the money we win. We know the card draw and coin flip are independent of each other while the money won is dependent on the combination the two.
Let the random variable X = {4, 1, -1} denote the money won. To find the amount of money we expect to win, plug this into our earlier definition:
E[X] = (p1)(4) + (p2)(1) +(p3)(-1)
Now, all that's left to do is calculate the probabilities, plug em in, and add it all up!
p1 = P(face card, heads) = P(face card)⋅P(heads)
p2 = P(face card, tails) = P(face card)⋅P(tails)
p3 = P(not a face card)
Hope this helps! Lemme know if you have any other questions.