Jeffrey K. answered 10/19/20
Together, we build an iron base in mathematics and physics
Hi Nathan.
This question involves the principle of Conservation of Momentum. That's a fancy way of saying that the total momentum never changes, that is, total momentum before the collision equals total momentum after.
Q 1) Momentum of car #1 = m1v1 = 618 x 7.9 = 4,882.2 kg m/s
Q 2) To find the mass of car #2, we need to consider the total momentum before and and after the collision.
The speed of car #2 is not given (shame on the questioner!) so we assume it is zero.
Therefore, total momentum before = m1v1 + m2v2
= 4,882.2 + m2 x 0
= 4,882.2
After the collision, the 2 trains act as a single body of mass m1 + m2
Therefore, total momentum after = (m1 + m2) vf
= (618 + m2) 4.8
Equating these 2 values: 4,88.2 = (618 + m2) 4.8
I leave it as an exercise for you to find m2.
Q 3) This is very similar to the above.
Total momentum before = 618 x 7.9 + m2 x (-5.6) . . . . . . . . . . and we know the value of m2
Total momentum after = (m1 + m2) vf . . . . . . . . . . . . . . . . . . vf = final velocity of the 2-car mass
Fill in the values of m1 and m2 , equate the above 2 values, and solve for vf