
Patrick B. answered 10/11/20
Math and computer tutor/teacher
THe product of an odd and an even is even: (2t)(2t+1) is divisible by 2.
Among N(N+1)(N+2) is at least one odd and one even.
THe product must be event...
Think of it this way, for integer t
The product looks like this (2t)(2t+1)(2t+2) = (4t)(2t+1)(t+2) which is divisible by 2
OR
The product looks like this (2t+1)(2t+2)(2t+3) = 2(2t+1)(t+1)(2t+3) which is also divisible by 2