Pb(NO3)2(aq)+2NH4I(aq)⟶PbI2(s)+2NH4NO3(aq) What volume of a 0.530 M NH4I solution is required to react with 929 mL of a 0.200 M Pb(NO3)2 solution?How many moles of PbI2 are formed from this reaction?

Answer 1

Hello, Bri,

I answered a similar problem, so please look at that one, which has a more detailed explanation. The only difference is that this one also asks for moles of one of the products. Keep in mind the definition of Molarity: moles solute/Liter solvent and be careful with the volume units since we are given volumes in ml, when we need Liters for the calculations. Everything should be 3 sig figs.

The moles PbI2 produced will be the same as moles Pb(NO)3, as per the balanced equation.

Bob