Hello, Bri,
I don't have the room for a complete explanation, but follow the logic and units.
Calculate the moles of Zn present in 7.35 grams. We can tell from the equation that we need twice as much HCl than Zn. So double the moles calculated for Zn and that will be the moles HCl required.
The HCl concentration is 5.5M. M is moles/Liter. To find the number of ml needed for 0.2248 moles of HCl, just set up the equation 5.5M = 0.2248moles/X, where X is volume in liters. Finally, convert liters into ml. I didn't pay attention to sig figs, but it should be 3. 1240 ml.
I hope this is useful,
Bob
