Rowan is a shot-putter for his school. If he exerts an unbalanced force of 140 N on a shot giving it an acceleration of 19 m/s². What is the mass of the shot? Show your work.

Question

this is for chemistry pleasee help

Answer 1

F=MA

force = mass x acceleration

140N = M x 19 m/s^2

M = 140N/19 m/s^2 = 140/19 kilograms = 7.37 kg

a Newton is the force needed to move 1 kilogram 1 m/sec^2

N/m/sec^2 = kg

(that's assuming "unbalanced" force didn't mean in a direction other than where the shotput went)

Answer 2

force = mass * acceleration

mass = force / acceleration = (140 N) / (19 m/s²) = (140 kg*m/s²) / (19 m/s²) = 7.368 kg

Answer 3

This uses Newton's laws of Motion.

F = ma

140N = mass*19m/s^2

divide out the acceleration to get mass isolated

Newtons = kg*m/s^2 = N

(140kg*m/s^2)/(19m/s^2) = 7.368 Kilograms # here I rounded to the third decimal place