A delivery of 12 large boxes and 2 small boxes has a total weight of 235. How much does each type of box weigh?

Answer 1

This is asking you to maximize. You would first need to set some variables. If u make the small box S and the large box L, you can come up with 2 equations to set equally to each other in order to solve for the other variable.

The 1st equation will be: 235=12 L + 2S

2nd equation: 235= L+ S

Solving for L and plugging back into 1st equation gives:

L=235-S

235= 12(235-S) + 2S now distribution gives us:

235= 2820-12S +2S. Now with this equation we solve for S

-2585= -10S

258.5=S

Plugging back into 2nd equation gives:

235= L + 258.5

so then that would mean that L= -23.5. So with this. So now we have how both variables relate to each other. If L= -23.5, S= 258.5, so when L= 1, S=234, for the 2nd equation. We can now plug one into the first equation to know the second variable for the 1st equation, which is the constraints for the numbers of boxes for each:

For the 1st equation with L= 1, S=111.5. You can switch the variables for it to make practical sense. You would have 2 of the boxes weighing 111.5lbs (most likely the large box) and 12 of the other boxes (small box) weighing 1 lb. Your answer should check out when plugged back in and should total to 235lbs.

235= 12(1) + 2(111.5)

Answer 2

Cameron,

There appears that more info is needed for this problem.